How do you solve #50w \div ( 90+ w ) = 20#?

1 Answer
Jan 15, 2018

See a solution process below:

Explanation:

First, rewrite the expression as:

#(50w)/(90 + w) = 20#

Next, multiply each side of the equation by #color(red)((90 + w))# to eliminate the fraction while keeping the equation balanced:

#color(red)((90 + w)) xx (50w)/(90 + w) = color(red)((90 + w)) xx 20#

#cancel(color(red)((90 + w))) xx (50w)/color(red)(cancel(color(black)(90 + w))) = color(red)(90 xx 20) + (w xx 20)#

#50w = 1800 + 20w#

Then, subtract #color(red)(20w)# from each side of the equation to isolate the #w# term while keeping the equation balanced:

#50w - color(red)(20w) = 1800 + 20w - color(red)(20w)#

#(50 - color(red)(20))w = 1800 + 0#

#30w = 1800#

Now, divide each side of the equation by #color(red)(30)# to solve for #w# while keeping the equation balanced:

#(30w)/color(red)(30) = 1800/color(red)(30)#

#(color(red)(cancel(color(black)(30)))w)/cancel(color(red)(30)) = 60#

#w = 60#