Question #be5eb
1 Answer
also
Explanation:
Let
We remember that
Thus
But the domain of trig functions extend to all real numbers, so it's useful to recall the graph of
graph{(y-cos(x))(y-sqrt3/2)=0 [-2, 6, -2, 2]}
Due to parity
and periodicity
of this function, the solutions are
where
But
Only solutions
are left.
First case
Second case
Union of sets of solutions from both cases gives us
Graph of arccos (with a line
graph{(x-cos(y))(x-pi/6)sqrt(y(pi-y))=0 [-4, 4, -0.5, 3.5]}
Useful links
https://www.wolframalpha.com/
https://www.wolframalpha.com/input/?i=arccos(pi%2F6)