How do you solve #42- 3x = 12- 8x#?

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Answer 1 · 2018-01-16T15:00:17

x = -6

#42−3x=12−8x#

#42-12=−8x+3x#

#30=−5x#

#x=-6#

Verification;
#42−3(-6)=12−8(-6)#

#42-(-18)=12−(-48)#

#60=60#

hence since LHS=RHS, x=-6! :)

-Sahar.