How do you solve #3+ ( 2x+ 5) = 117#?

1 Answer
Jim G.
Jan 16, 2018

#x=109/2#

Explanation:

#"distribute the bracket"#

#3+2x+5=117#

#rArr2x+8=117#

#"subtract 8 from both sides"#

#2xcancel(+8)cancel(-8)=117-8#

#rArr2x=109#

#"divide both sides by 2"#

#(cancel(2) x)/cancel(2)=109/2#

#rArrx=109/2#

#color(blue)"As a check"#

Substitute this value into the left side of the equation and if it equals the right side then it is the solution.

#3+(cancel(2)xx109/cancel(2)+5)=3+114=117#

#rArrx=109/2" is the solution"#

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