What is the formula of pressure according to kinetic theory in terms of mass density ?

In my book, the formula given is #P= 1/3 nm(v^2)_(av)# where n is number density, m is mass of one molecule and

#(v^2)_(av)# is average of square of all speeds in random direction. Now, if I were to write formula for P in terms of mass density i.e #rho = m/V#, it should be

#P= 1/3Nrho(v^2)_(av)# where N is number of molecules but the formula given in my book for this case is

#P=1/3rho(v^2)_(av)#. What is the correct formula?

1 Answer
Jan 17, 2018

There is error in calculation of #rho#.
In the equation (1) #m# is defined as mass of one molecule. While calculating #rho#, #m# has been taken as total mass of gas sample.

Explanation:

Given

#P= 1/3 nmbar(v^2)# .....(1)
where #n# is number density, #m# is mass of one molecule and #bar(v^2)# is average of square of all speeds in random direction.

Now, writing formula for #P# in terms of mass density #rho# we see that

#rho = "Total mass"/"Volume"#

#=>rho = nm#
#n# being number density already stated.

Inserting in (1) we get

#P= 1/3rhobar(v^2)#