What are the first four terms of the sequence #r(n)=4.5n-8# ?

1 Answer
Kai
Jan 18, 2018

The first four terms are #-3.5, 1, 5.5, 10#

Explanation:

To solve this, simply plug 1, 2, 3, and 4 into the original function.

#r(1)=4.5(1)-8=-3.5#

#r(2)=4.5(2)-8=1#

#r(3)=4.5(3)-8=5.5#

#r(4)=4.5(4)-8=10#

So, the first four terms are #-3.5, 1, 5.5, 10#

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