Question #29971

2 Answers
Sean
Jan 18, 2018

#a=(dsqrt2)/2#

Explanation:

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Triangle #DeltaABC# is an isosceles right triangle. This means:

#/_B=90^@#

#AB=BC=a#

The Pythagorean formula says:

#d^2=a^2+a^2#

#d^2=2a^2#

#a^2=d^2/2#

#a=d/sqrt2=(dsqrt2)/2#

Ujjwal
Jan 18, 2018

You can divide the diagonal by #√2#

Explanation:

Use pythogoras theroem
You get,
#(side)^2 + (side)^2 = +(diagonal)^2#
# 2(side)^2 = (diagonal)^2#
# sqrt[2(side)^2] = diagonal#
# sqrt2*side = diagonal#
With this relation you can get what you want.

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