You have a gold nugget that has a mass of #50.5*g#. What is the volume of your nugget given that #rho_"Au"=19.3*g*mL^-1#?

2 Answers
Jan 18, 2018

#974.65# ml

Explanation:

#D = M/V# (density = mass / volume)

this can be rearranged to give #V = D/M# (volume = density / mass)

#V = 19.3#g/ml #// 50.5#g

#19.3/50.5 = 974.65#

#V = 974.65# ml

volume of gold = volume of water that gold displaces

Jan 18, 2018

Well, what is the volume of your gold nugget....?

Explanation:

By definition, #rho_"density"="mass"/"volume"#

We are given #rho_"Au"=19.3*g*mL^-1#...

And so #"volume"="mass"/rho_"Au"=(50.5*g)/(19.3*g*mL^-1)=2.62*mL#....and it would displace this volume of water.

A more interesting question is how much is the nugget worth? The current price of gold is #$43-70*USD*g^-1#...how much is your nugget worth?