Question

Question #b5a72

Answer 1

Simplify the expression first

Explanation:

`((216πr^2-2πr^5)/(3r^2))+2πr^2`

Fisrt get rid of the r^2 in the denominator:

`(216π−2πr^3)/(3)+2πr^2`

It seems easier now:

`(216π)/3−(2πr^3)/(3)+2πr^2`

So the derivate will be:

`0- (2pi*3r^2)/3+2pi*2*r`

`0- 2pir^2+4pir`