Question

Question #6d6cb

Answer 1

0.15L

Explanation:

For dilutions remember the equation

`V_1*C_1=V_2*C_2`

`V_1` is volume 1 (initial)
`C_1` is concentration 1 (initial)
`V_2` is volume 2 (after)
`C_2` is concentration 2 (after)

In your case,

`V_1` is ?
`C_1` is 0.5M
`V_2` is 500mL
`C_2` is 0.15M

So;

`V1*0.5 = 0.5*0.15`
`V_1 = (0.5*0.15)/0.5`
`V_1` = 0.15L