Question #6d6cb

1 Answer
Jan 18, 2018

0.15L

Explanation:

For dilutions remember the equation

#V_1*C_1=V_2*C_2#

#V_1# is volume 1 (initial)
#C_1# is concentration 1 (initial)
#V_2# is volume 2 (after)
#C_2# is concentration 2 (after)

In your case,

#V_1# is ?
#C_1# is 0.5M
#V_2# is 500mL
#C_2# is 0.15M

So;

#V1*0.5 = 0.5*0.15#
#V_1 = (0.5*0.15)/0.5#
#V_1# = 0.15L