Question #0e707

Question

747 views around the world

You can reuse this answer
Creative Commons License

Answer 1 · 2018-01-19T01:38:57

The helium neon laser typically operates at #632.8# #nm.#

Thus the energy contained in a single photon from the laser is:

#E=hf=hc/lambda=(6.63times10^(-34))(3times10^8)/(632.8times10^(-9))#

#=3.143times10^(-19)J#

If the laser operates at #90# #wa t t=90# #Js^-1# then the amount photons emitted per second will be:

Power output of laser/ Energy of photon.

#=90/(3.143times10^(-19))=2.863times10^20# #s^-1#