How do you simplify #\frac { - 3} { 2} ( \frac { x ^ { 3} y ^ { - 6} } { x ^ { - 14} y ^ { - 3} z } ) ^ { 0}#?

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Answer 1 · 2018-01-19T17:48:25

#-3/2#

to solve: #n^0 = 1#

assuming that #x,y,z != 0# (so that the denominator is not #0#):

#((x^3y^(-6))/(x^-14y^-3z)) = 1#

#((x^3y^(-6))/(x^-14y^-3z)) = -3/2 * 1#

#= -3/2#

if #x,y# or # z = 0#, then #((x^3y^(-6))/(x^-14y^-3z))# is undefined

if #x,y,z != 0#, then #((x^3y^(-6))/(x^-14y^-3z)) ^0 = 1#