The infinite geometric sequence(Xn)?

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1 Answer
Jan 19, 2018

#"see explanation"#

Explanation:

#(a)#

#"the fist term in the sequence is "a=6.5#

#"the common ratio r is found as follows"#

#r=a_2/a_1=a_3/a_2= ...... =a_n/a_(n-1)#

#rArrr=(-27.3)/6.5=114.66/(-27.3)=-4.2#

#"sequence "=a,ar,ar^2,ar^3, ...... ,ar^(n-1)#

#(b)#

#"the n th term is"#

#a_n=ar^(n-1)#

#(c)#

#"here "a=6.5,r=-4.2" and "n=8#

#rArra_8=6.5xx(-4.2)^7~~-149850.567" 3 dec. places"#

#(d)#

#"the sum to n terms of a geometric sequence is"#

#•color(white)(x)S_n=(a(1-r^n))/(1-r)=(a(r^n-1))/(r-1)#

#"if "-1 < r<1to|r|<1#

#"then the sum will converge on a particular value"#

#"as "ntooo,r^nto0#

#rArrS_n=(a(1-0))/(1-r)=a/(1-r)larrcolor(blue)"sum to infinity"#

#"and is written as "S_oo=a/(1-r)#

#"if "r>1," then as "ntooo,r^ntooo" and "S_nto+-oo#
#"dependent on the sign of a"#

#"if "r<-1," then as "ntooo#

#S_n" alternates between being large and positive and "#
#"large and negative"#

#"here " r=-4.2<-1#

#"as an example"#

#S_(30)=(6.5((-4.2)^(30)-1))/(-4.2-1)larrcolor(blue)"large and negative"#

#S_(35)=(6.5((-4.2)^(35)-1))/(-4.2-1)larrcolor(blue)"large and positive"#