Through (1,7); parallel to the line passing through (2,5) and (-2,1)?

1 Answer
Jan 20, 2018

First, calculate what the slope of a line through (2, 5) and (-2, 1) would be.

m = (y_1 - y_2)/(x_1 - x_2)

m = (5 - 1)/(2 - (-2))

color(red)m = 1

A line parallel to this must have the same slope.

y = color(red)1x + b

y = x + b

We can now substitute in our known point (color(green)1, color(blue)7) to find the y-intercept.

color(blue)7 = color(green) 1 + b

6 = b

And now, we can write the equation of this line as we know both the slope and the y-intercept.

y = x + 6