How do you find the limit of #(2x-3)/(x+5)# as #x->3#?
1 Answer
Explanation:
#"evaluate using direct substitution"#
#lim_(xto3)(2x-3)/(x+5)=(6-3)/(3+5)=3/8#
Note that this works because the function is continuous at
Note:
#"evaluate using direct substitution"#
#lim_(xto3)(2x-3)/(x+5)=(6-3)/(3+5)=3/8#
Note that this works because the function is continuous at
Note: