Question

If `f(n) = 2n^2+5n`, what is `f(0)`?

Answer 1

See a solution process below:

Explanation:

For each occurrence of `color(red)(n)` in `f(n)` substitute `color(red)(0)` and calculate the result:

`f(color(red)(n)) = 2color(red)(n)^2 + 5color(red)(n)` becomes:

`f(color(red)(0)) = (2 xx color(red)(0)^2) + (5 xx color(red)(0))`

`f(color(red)(0)) = (2 xx 0) + (5 xx color(red)(0))`

`f(color(red)(0)) = 0 + 0`

`f(color(red)(0)) = 0`