How do you solve #12s - 30= 16s - 70#?

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Answer 1 · 2018-01-20T23:21:58

See a solution process below:

First, subtract #color(red)(12s)# and add #color(blue)(70)# to each side of the equation to isolate the #s# term while keeping the equation balanced:

#12s - color(red)(12s) - 30 + color(blue)(70) = 16s - color(red)(12s) - 70 + color(blue)(70)#

#0 + 40 = (16 - color(red)(12))s - 0#

#40 = 4s#

Now, divide each side of the equation by #color(red)(4)# to solve for #s# while keeping the equation balanced:

#40/color(red)(4) = (4s)/color(red)(4)#

#10 = (color(red)(cancel(color(black)(4)))s)/cancel(color(red)(4))#

#10 = s#

#s = 10#

Answer 2 · 2018-01-20T23:23:36

#s=10#

first subtract #12s to 16s# then you get #-30=4s-70#
then add #70 to -30# then divide #40/4#

Answer 3 · 2018-01-20T23:23:57

s = 10.

We set the entire equation equal to zero.

#12s - 30 = 16s -70#

We can do that by subtracting #16s# and #-70# from both sides. Note that subtracting a negative number is the same as adding.

#12s - 30 -16s -(-70) = 0#

Then we simplify:

#12s -16s - 30 + 70 = 0#

#-4s + 40 = 0#

We can then add #-4s# to both sides of the equation to isolate #s#, and divide both sides by 4 to solve for #s#:

#40 = 4s#

#10 = s#