Question #b7835
2 Answers
Explanation:
Remember the chain rule: for
Here,
Power rule:
Remember that
So now we have
But remember,
Explanation:
"differentiate using the "color(blue)"chain rule"differentiate using the chain rule
"given "y=f(g(x))" then"given y=f(g(x)) then
dy/dx=f'(g(x))xxg'(x)larrcolor(blue)"chain rule"
4/(2x-1)=4(2x-1)^-1
rArrd/dx(4(2x-1)^-1)
=-4(2x-1)^-2xxd/dx(2x-1)
=-8/(2x-1)^2