Question

Question #7a137

Answer 1

The three numbers are `54`, `324` and `154`.

Explanation:

Call the first number '`n`', then the second number is `6n` and the third is `n+100`.

We know the total of the three numbers is `n+6n+n+100=532`.

Collecting like terms, `8n+100=532`, then `8n=432`, so `n=432/8=54`.

The second number is `6` times `n`, so `6xx54=324`.

The third is `n+100=154`.

Answer 2

54, 154, & 324

Explanation:

To solve this, we'll call the first number `x` .
Using this variable, we can create equations for the remaining two equations.
The second number we'll call `y`. It is 6 times the first so
`y=6x` .
The third number we'll call `z`. It is 100 more than the first so
`z=100 + x`.
The sum of all three numbers is `x+y+z=532`.
Substituting in our equations we get `x + (6x) + (100+x) = 532` which simplifies to `8x=432`.
We get `x=54`, `y=6(54)=324`, and `z=100+54=154`.