There are two jars of marbles. The first jar has 4 black and 4 white marbles. The second jar has 6 black and 2 white marbles. One marble is drawn from each jar. What is the probability of drawing a black marble from both jars?

2 Answers
Jan 23, 2018

#5/8#.

Explanation:

Total number of outcomes=
#(4+4) + (6+2)#
=#16#
No. of black marbles= 4+6
= #10#
Probability of drawing a black marble= #10/16#
= #5/8#

Jan 27, 2018

The probability of drawing a black marble from both jars is #3/8,# or 37.5%.

Explanation:

Since we are making two independent draws, the probability we seek is the product of the probability for success on both draws. In math terms:

#"P"("both black")="P"("1st is black") xx "P"("2nd is black")#

Since the draws are both made at random, the probability that the first marble is black is the ratio of black marbles to all marbles:

#"P"("1st is black") = 4/(4+4)" "("black"/"black + white")#

#color(white)("P"("1st is black")) = 4/8#

#color(white)("P"("1st is black"))=1/2#

Similarly, the probability of drawing a black marble from the second jar is:

#"P"("2nd is black") = 6/(6+2)" "("black"/"black + white")#

#color(white)("P"("2nd is black")) = 6/8#

#color(white)("P"("2nd is black"))=3/4#

Finally, the probability that both draws are black is the product of these two independent probabilities:

#"P"("both black")="P"("1st is black") xx "P"("2nd is black")#

#color(white)("P"("both black"))=1/2 xx 3/4#

#color(white)("P"("both black"))=3/8#