Question

How do you find the corresponding rectangular coordinates for the point `(-1, (-3pi)/4 )`?

Answer 1

The rectangular form is `( (sqrt(2))/2, (sqrt(2))/2 )`.

Explanation:

We can use `x=rcos(theta)` and `y=rsin(theta)` to convert:

`x=-1cos(-(3pi)/4)=-1(-sqrt(2)/2)=(sqrt(2))/2`
`y=-1sin(-(3pi)/4)=-1(-sqrt(2)/2)=(sqrt(2))/2`

So the rectangular form is `( (sqrt(2))/2, (sqrt(2))/2 )`.