Question

An object with a mass of `5 kg` is revolving around a point at a distance of `3 m`. If the object is making revolutions at a frequency of `1 Hz`, what is the centripetal force acting on the object?

Answer 1

`60π^2N`

Explanation:

`"Centripetal force" = (m*v^2)/r`
The frequency was given as 1hz
Then `"angular velocity" =2πf =(2π" rad")/s`
Remember that `"linear velocity" = "angular velocity"*"distance"`
`V=romega`
Substituting this into the centripetal force formular
`F= (m*romega*romega)/r`
`F=mrw^2`
So using this
`F=5 * 3 * 2π * 2π`
`F=60 * π^2N`