Question

If `h( n ) = 4n - 5` and `g ( n ) = 2n ^ { 2} - 1`, what is `( h \circ g ) ( n )`?

Answer 1

`(h @ g) (n) = 8n^2-9`

Explanation:

`(h @ g) (n) = h(g(n)) ; g(n)=2n^2-1 ; h(n)= 4n-5`

`:.(h @ g) (n) = h(2n^2-1) = 4(2n^2-1)-5` or

`(h @ g) (n) = h(2n^2-1) = 8n^2-4-5` or

`(h @ g) (n) = 8n^2-9` [Ans]