How do you solve #0.19y + 0.02( y + 2000) = 1300#?

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Answer 1 · 2018-01-25T11:59:28

#y=6000#

#0.19y + 0.02(y+2000) = 1300#

You can solve this by "expanding" the brackets. We rewrite the equation as follows.

#0.19y + (0.02*y+0.02*2000) = 1300#
#0.19y+0.02y+40=1300#

Next we isolate the variable.

#0.21y +40-40 = 1300-40#
#0.21y = 1260#

#(0.21y)/0.21 = 1260/0.21#

#y=6000#