Question

How do you solve `\ln 2+ \ln ( x - 10) = 2`?

Answer 1

Solution: `x ~~13.6945`

Explanation:

`ln 2 +ln(x-10) =2 or ln 2(x-10) =2 or 2(x-10)=e^2`

[ `ln(mn)= ln m +ln n ;`and `ln N=x if e^x= N` ]

`2(x-10)=e^2 or x-10=e^2/2`or

`x= e^2/2+10~~13.6945 (4dp)`

Solution: `x ~~13.6945` [Ans]