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Answer 1 · 2018-01-28T04:41:13

#25 and 18#

Let one number be #x# and other number be #y#

Then, #x+y# = #43#...........(#1#)
and #x-y# = 7.................(#2#)

Add both the equations and we get,

#2x=50#
or#x# = #cancel50^25/cancel2^1# = #25#

Put the value of #x# in any of the above two equations to get the value of #y#

Let's put it in equation #1#

#25+y = 43#
or, #y = 43-25# =#18#

Answer 2 · 2018-01-28T04:54:50

The first number is #18# and the second number is #25#.

You can begin by writing this question algebraically.

#x + y = 43#

#y = x + 7#

We can combine these expressions.

#x + ( x + 7 ) = 43#

#2x color(red)(cancel(color(black)(+ 7)- 7)) = 43 color(red)(-7)#

#color(red)((cancel(color(black)(2))color(black)(x))/cancel(2) = color(black)(36/color(red)(2))#

#x = 18#

#y = x + 7#

#y = 25#

We can prove that #x = 18# and #y = 25# because #x + y = 43#, or #18 + 25= 43#.