Question

How do you graph `y=1/4x+.5` and `y=-2x-4` on the same axis?

Answer 1

See below.

Explanation:

The equation of a straight line in slope/intercept form is:
`y=mx+c`: where slope `=m and y-`intercept `=c`

In this example:

`y = 1/4x+0.5` [A]
`y = -2x-4` [B]

Both [A] and [B] are equations of straight lines.

[A] has a slope of `1/4` and a `y-`intercept of `0.5`

[B] has a slope of `-2` and a `y-`intercept of `-4`

We can graph [A] and [B] on the same `xy-`plane as below.

graph{(x/4+0.5-y)(-2x-4-y)=0 [-16.02, 16.01, -8.01, 8]}

NB: From the graph we can see the solution of the system of linear equatons [A] and [B] is `x=-2, y=0`