Question #06104

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A08
Jan 28, 2018

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Refer to the figure above. Tractor is parked on the incline and is at rest. To keep it in the state of equilibrium, downward force along the incline #mgsintheta# should be balanced by the force of friction #f# given as #muN#.

#:.f=mgsintheta#
where #m# is mass of tractor, #g=9.81" ms"^-2# is acceleration due to gravity.

Inserting given values we get

#f=2000xx9.81xxsin25^@#
#=>f=8292" N"#

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