Question #994ee

1 Answer
Barry H.
Jan 29, 2018

#-sin[x-y]/[1-sin[x-y]]#

Explanation:

Using the chain rule and implicit differentiation,
#dy/dx =-sin[x-y]d/dx[x-y]#

#dy/dx=-sin[x-y][1-dy/dx]#

#-dy/dx/[sin[x-y]+dy/dx=1#

#-dy/dx[1/sin[x-y]-1]=1#

#dy/dx=-1/[1/[sin[x-y]]+1]#

#dy/dx=-1/[1-sin[x-y]]/[sin[x-y]]#

#dy/dx=-sin[x-y]/[1-sin[x-y]]#

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