Question

How many atoms are contained in 0.10 grams of copper?

Answer 1

This is `9.47xx10^(20)` atoms.

Explanation:

The mass of one mole of copper is 63.55 g. So, 0.10 g is equal to

`0.10 g -: 63.55 g/"mol" = 0.001574 "mol"`

Next, we convert moles into # of atoms, using Avogadro's number:

`0.001574 xx 6.02xx10^(23) = 9.47xx10^(20)` atoms