# Z=(1-2i)/(6+i)#
#Z=a+ib #. Modulus: #|Z|=sqrt (a^2+b^2)#;
Argument:#theta=tan^-1(b/a)# Trigonometrical form :
#Z =|Z|(costheta+isintheta)#
#Z_1= 1-2 i #.Modulus:#|Z|=sqrt(1^2+(-2)^2) #
#=sqrt 5 ~~ 2.236# Argument: #tan alpha= (|-2|)/(|1|)#
#=2 #. #alpha =tan^-1 2 = 1.107; Z_1# lies on fourth quadrant, so
#theta =2pi-alpha=2pi-1.107 ~~ 5.176#
# :. Z_1=2.236(cos5.176+isin 5.176) #,
#Z_2= 6 + i #.Modulus:#|Z|=sqrt(6^2+1^2) #
#=sqrt 37 ~~ 6.083# Argument: #tan alpha= (|1|)/(|6|)#
#=1/6 :.alpha =tan^-1 (1/6) = 0.165 ; Z_2# lies on first quadrant,
#:. theta=alpha ~~0.165# # :. Z_2=6.083(cos 0.165+isin 0.165) #
# Z=(1-2i)/(6+i)#
# Z= (2.236(cos5.176+isin 5.176))/(6.083(cos 0.165+isin 0.165)#
#Z=0.368(cos(5.176-0.165)+isin (5.176-0.165))# or
#Z=0.368(cos 5.011+isin 5.011) =4/37-13/37i#
In trigonometric form: #0.368(cos 5.011+isin 5.011)# [Ans]