How do you solve #-0.5( n + 2) ^ { 2} = 0#?

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Answer 1 · 2018-02-01T02:55:08

#color(green)(n = -2#

#-0.5 (n+2)^2 = 0#

#(n+2)^2 = 0 / -0.5 = 0# as 0/ anything other than 0 is 0.

#(n+2)^2 = (n+2) * (n+2) = 0#

#:. n+2 = 0 (n+2) = 0.#

Taking constant term to R H S,

#n + cancel2 - cancel2 = 0 - 2 = -2#

#n = -2#