What is the standard form of #y= (x-x^2)(x-8) -(x+3)^3#? Algebra Polynomials and Factoring Polynomials in Standard Form 1 Answer Barney V. Feb 1, 2018 #y=-2x^3-35x-27# Explanation: #y=(x-x^2)(x-8)-(x+3)^3# #:.y=(x-x^2)(x-8)-(x+3)(x+3)(x+3)# #:.y=-x^3+9x^2-8x-(x^3+9x^2+27x+27)# #:.y=-x^3+9x^2-8x-x^3-9x^2-27x-27# #:.y=-2x^3-35x-27# Answer link Related questions What is a Polynomial? How do you rewrite a polynomial in standard form? How do you determine the degree of a polynomial? What is a coefficient of a term? Is #x^2+3x^{\frac{1}{2}}# a polynomial? How do you express #-16+5f^8-7f^3# in standard form? What is the degree of #16x^2y^3-3xy^5-2x^3y^2+2xy-7x^2y^3+2x^3y^2#? What is the degree of the polynomial #x^4-3x^3y^2+8x-12#? What is the difference between a monomial, binomial and polynomial? How do you write #y = 2/3x + 5# in standard form? See all questions in Polynomials in Standard Form Impact of this question 1241 views around the world You can reuse this answer Creative Commons License