How do you solve #47> 4u - 9#?

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Answer 1 · 2018-02-01T16:32:07

See a solution process below:

First, add #color(red)(9)# to each side of the equation to isolate the #u# term while keeping the equation balanced:

#47 + color(red)(9) > 4u - 9 + color(red)(9)#

#56 > 4u - 0#

#56 > 4u#

Now, divide each side of the equation by #color(red)(4)# to solve for #u# while keeping the equation balanced:

#56/color(red)(4) > (4u)/color(red)(4)#

#14 > (color(red)(cancel(color(black)(4)))u)/cancel(color(red)(4))#

#14 > u#

We can reverse or "flip" the entire inequality to state the solution in terms of #u#

#u < 14#