Question

At `-35` `""^@C`, and `5.8*atm` pressure, how many moles of gas are present?

Answer 1

Let us assume that you have a volume of `1*L`...I make it about `0.2*mol`..........

Explanation:

And we must assume a volume because, pressure is a state function of volume, temperature, and amount of gas...

And we must use absolute temperature....`-35` `""^@C` `-=` `308.15*K`...and so...

`n=(PV)/(RT)=(5.8*cancel(atm)xx1*cancelL)/(0.0821*cancel(L*atm)*cancel(K^-1)*mol^-1xx308.15*cancelK)`...

`=??*mol`

...we get an answer in `1/(mol^-1)-=1/(1/(mol))=mol` as required...