At what height above the earth surface the value of g is 1/2 of its value on earth surface.Given its radius 6400km.?
1 Answer
Feb 2, 2018
If the height from the surface of the earth is
#color(red)(h# and the radius of the earth is#color(red)(R# ,then the relation between the final gravitational acceleration is
#color(red)(ul(bar(|color(green)(g^(')=g(1-(2h)/R))|# According to your given condition,
#g^'=g/2# Apply formula:-
#g/2=g(1-(2h)/R)#
#=>1/2=1-(2h)/R#
#=>1/2=(2h)/R#
#=>color(red)(h=R/4=6400/4=1600"km"# Hope it helps...
Thank you...