How do you divide #(2x^3 - 6x^2 + 8) / (x^2 - 4)#?

1 Answer
Barney V.
Feb 2, 2018

Explanation:

#(2x^3-6x^2+8)/(x^2-4)#

#color(white)(........)color(white)(.)2x-6#
#x^2-4|overline(2x^3-6x^2 color(white)(......)+8)#
#color(white)(............)ul(2x^3 color(white)(.........)-8x#
#color(white)(................)-6x^2+8x+8#
#color(white)(..................)ul(-6x^2 color(white)(.......)+24)#
#color(white)(..............................)8x-16#

#(2x^3-6x^2+8) / (x^2-4) = 2x-6 # and remainder of # (8x-16)/(x^2-4)#

Related questions
See all questions in Division of Polynomials
Impact of this question
1173 views around the world
You can reuse this answer
Creative Commons License