What mass of carbon dioxide results from the complete combustion of 359*g propane, and 359*g methane?

1 Answer
Feb 4, 2018

Approx. 1*kg...

Explanation:

We assume complete combustion according to (i):

CH_4(g) +2O_2(g) rarr CO_2(g) +2H_2O(l)

"Moles of methane"=(359*gxx32.6%)/(16.04*g)=7.30*mol

And (ii):

C_2H_6(g) +7/2O_2(g) rarr 2CO_2(g) +3H_2O(l)

"Moles of propane"=(359*gxx67.4%)/(30.04*g)=8.05*mol

And so, WITH RESPECT to carbon dioxide, we gets....

(7.30*mol+2xx8.05*mol)xxunderbrace(44.01*g*mol^-1)_"molar mass of carbon dioxide"~=1*kg

Take that environment....