Question

Question #6e6e9

Answer 1

Locate the hose 14.5 m from the building.

Explanation:

First, we resolve the initial velocity `v_i` into its `x`- and `y`-components:

`v_x`=v_ocos34.2°=17.4m/s#

`v_y`=v_osin34.2°=11.8m/s#

When the water reaches its greatest height, its vertical speed will be zero (otherwise, it would either still be going up, or coming down).

We will find the time taken to reach the building:

`v=v_i-g*t`

`0=11.8 - 9.8t`

`t=(11.8)/(9.8) = 1.20 s`

This means the water also has 1.20 s to travel horizontally toward the building, and travels a distance:

`x=v_x*t= 17.4 m/s * 1.20s=14.5 m`