Question

What is the antiderivative of `(sinx)*(cosx)`?

Answer 1

`intsinxcosxdx=-1/2cos2x`

Explanation:

Antiderivative of `sinxcosx` means

`intsinxcosxdx`

= `intsin2xdx` and let `u=2x` then `du=(dx)/2`

and hence `intsin2xdx=1/2intsinudu`

= `-1/2cosu=-1/2cos2x`