How do you solve #10= 2e^ { 5x }#?
2 Answers
Feb 5, 2018
Explanation:
#"using the "color(blue)"law of logarithms"#
#•color(white)(x)logx^nhArrnlogx#
#"divide both sides by 2"#
#rArre^(5x)=10/2=5#
#"take the ln (natural log) of both sides"#
#rArrlne^(5x)=ln5#
#rArr5xcancel(lne)^1=ln5#
#rArrx=ln5/5~~0.322" to 3 dec. places"#
Feb 5, 2018
x=ln(5)/5
Explanation:
or
Take natural log on both sides
Using property
0r
ln(5)=5x [since ln(e)=1 ]
x=ln(5)/5