How do you find the slope of the secant lines of #f(x) = -x^2# through the points: [-2, -4]?
1 Answer
Feb 8, 2018
Explanation:
#"the slope of the secant line is"#
#•color(white)(x)(f(b)-f(a))/(b-a)#
#f(b)=f(-2)=-(-2)^2=-4#
#f(a)=f(-4)=-(-4)^2=-16#
#rArr(-4-(-16))/(-2-(-4))=12/2=6#
