Question

A model train with a mass of `5 kg` is moving along a track at `16 (cm)/s`. If the curvature of the track changes from a radius of `88 cm` to `28 cm`, by how much must the centripetal force applied by the tracks change?

Answer 1

The `DeltaF=0.3117`

Explanation:

Assuming constant velocity and mass.

`DeltaF=F_2-F_1`
The change in force is equivalent to the force being applied currently subtracted from the force that will be applied.

Physics is always in Kilograms, Meters, and Seconds . So convert.

`F_"Centripital"=[(mass)*(velocity)^2]/(radius)`

Use the equation to plug into our formula for `DeltaF`

`DeltaF=[(m_2)*(v_2)^2]/(r_2)-[(m_1)*(v_1)^2]/(r_1)`

`DeltaF=[(5)*(0.16)^2]/(0.28)-[(5)*(0.16)^2]/(0.88)`