How do you evaluate #(- - 4) ^ { 2} - 8\cdot - 4- 9#?

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Answer 1 · 2018-02-10T06:55:29

The answer is #71#

Assuming the equation is

#(--4)^2-(8*-4)-9#

Since #--a=+a=a#, The equation becomes

#4^2-(8*-4)-9#

As we multiply first in this equation

Since #4^2=16# and #-4*8=-64#, the equation becomes,

#16-(-64)-9# Then, The equation Simplifies to,...
#16+64-9#

#71#