How do you use the important points to sketch the graph of #y= 2x^2#?

1 Answer
Feb 10, 2018

Please see the explanation.

Explanation:

Given:

#color(blue)(y=2x^2 " "# Input Function

A quadratic function has a general form:

#color(red)(f(x) = ax^2+bx+c#

Referring to the Input Function that we have,

#a = 2; b = 0 and c=0#

Vertex of a quadratic function in general form

#Vertex: (-b)/(2a#

#Vertex: (-0)/(2(2)] = 0#

This value is the x coordinate of our vertex.

To find the y coordinate value of our vertex, substitute in our Input Function

#y=2(0)^2=0#

Hence, our Vertex is at #(0,0)#

Using a spreadsheet software, we can enter some values for #x# and find the corresponding y values:

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Refer to the image of the graph available below to comprehend the behavior of #color(blue)(y=2x^2 " "#

enter image source here