Solve cos^3x=cosxcos3x=cosx?
Cos^3x=cosxcos3x=cosx I get got the 0, pi/2, pi0,π2,π but I cant get (3pi)/23π2 . If anyone can help out I would really appreciate it.
2 Answers
See below
Explanation:
It's a little tricky, but try setting the equation = 0
Now factor out
And now factor the difference of two squares
Set each factor equal to 0 and solve using your unit circle
1)
2)
3)
See below.
Explanation:
Pythagorean identity: