Question

Question #8cc77

Answer 1

58.5 kg

Explanation:

`K=1/2mv^2`

`mv^2=2K`

`m=(2K)/v^2`

`v=constant = average speed = (1xx10^2m)/(8.8s)`
`K= 3.3.99xx10^3`

Substitute these values into the m equation above,

`m=(2K)/v^2= (2*3.99xx10^3J)/((1xx10^2m)/(8.8s))^2=58.5 J/(m^2/s^2)= 58.5 (kg cancel(m^2//s^2))/cancel(m^2//s^2)=58.5 kg`