Question #8cc77

1 Answer
Feb 11, 2018

58.5 kg

Explanation:

K=1/2mv^2

mv^2=2K

m=(2K)/v^2

v=constant = average speed = (1xx10^2m)/(8.8s)
K= 3.3.99xx10^3

Substitute these values into the m equation above,

m=(2K)/v^2= (2*3.99xx10^3J)/((1xx10^2m)/(8.8s))^2=58.5 J/(m^2/s^2)= 58.5 (kg cancel(m^2//s^2))/cancel(m^2//s^2)=58.5 kg