Question #26240

1 Answer
Feb 12, 2018

"please review the details below."

Explanation:

"The sum of the momentums before the hammer was thrown."

v_a=0
m_a=70 kg

v_h=0
m_h=4kg

P_b=m_a*v_a+m_h*v_h
P_b=70*0+4*0=0

"The sum of the momentums after the hammer was thrown."

m_a=70kg
v_a=3 ms^-1

m_h=4kg
v_h=v=?

P_a=m_a*v_a+m_h*v_h

P_a=70*3+4v

P_a=210+4v

"Since the momentum is conserved, we can write the following equation."

P_b=P_a

0=210+4v
-210=4v

v=-210/4

v=-52.5 ms^-1" should be thrown in the opposite direction."