Question #82330

1 Answer
Feb 12, 2018

#2 sinx#

Explanation:

#(cosx divide cotx) + sinx#

We know , #cotx = cosx/sinx#

Put this value in the above equation

#(cosx divide cosx/sinx) + sinx#

#(cosx * sinx/cosx) + sinx#

#(cancel cosx * sinx/(cancel cosx)) + sinx#

# ->sinx + sinx#

# ->2 sinx#