Question #82330

1 Answer
Feb 12, 2018

2 sinx2sinx

Explanation:

(cosx divide cotx) + sinx(cosx÷cotx)+sinx

We know , cotx = cosx/sinxcotx=cosxsinx

Put this value in the above equation

(cosx divide cosx/sinx) + sinx(cosx÷cosxsinx)+sinx

(cosx * sinx/cosx) + sinx(cosxsinxcosx)+sinx

(cancel cosx * sinx/(cancel cosx)) + sinx

->sinx + sinx

->2 sinx