Question

A sample of gas under a pressure of `241.3*mm*Hg`, and which expresses a volume of `365.2*mL` has been compressed from a volume of `478.2*mL`. Under what pressure was the gas initially?

Answer 1

We assume a constant temperature....

Explanation:

And so `P_1V_1=P_2V_2`...and we solve for ...

`P_1=(P_2V_2)/V_1`

We are given

`P_2=241.3*"Torr"=241.3*mm*Hg-=(241.3*mm*Hg)/(760*mm*Hg*atm^-1)=0.3175*atm`

`P_1=(0.3175*atmxx478.2*mL)/(365.2*mL)=0.416*atm`

`-=316.0*mm*Hg`...